Pozz solve it.. ....

1.	Pozz solve it.. ....
Answer» AnswEr : $\\ \\$ $\star \sf \: Given\begin{cases} \: \: \: { \bf{Possible \: events = 6 }}\\ \\ \: \: \:{ \bf{No. \: on \: dice = 1,<klux>2</klux>,3,4,5 \: and \: 6}} \end{cases}$ $\\$ Now, we know the required formula for finding Probability. That is, $\\$ $\: \: \: \: \star \: \: {\boxed{ \sf{ \purple{Probability = \dfrac{No. \: of \: favourable \: outcomes}{Total \: no. \: of \: favourable \: outcomes}}}}}$ (I) A Prime Number : $\\$ Prime numbers = 2, 3 & 5 $\\$ No. of favourable outcomes = 3 $\bigstar \:{ \underline{\sf \: Probability : }} \\ \\ : \implies\sf \: \dfrac{3}{6} \\ \\ : \implies\sf \: \blue{\dfrac{1}{2}} \\ \\$ (ii) A number lying between 2 and 5 : $\\$ Number's lying between 2 and 5 = 3 & 4 $\\$ No. of favourable outcomes = 2 $\bigstar \:{ \underline{\sf \: Probability : }} \\ \\ : \implies\sf \: \dfrac{2}{6} \\ \\ : \implies\sf \: \green{\dfrac{1}{3}} \\ \\$ (III) An EVEN number : $\\$ Even numbers = 2, 4 & 6 $\\$ No. of favourable outcomes = 3 $\bigstar \: { \underline{\sf \: Probability : }} \\ \\ : \implies\sf \: \dfrac{3}{6} \\ \\ : \implies\sf \: \orange{\dfrac{1}{2}} \\$

Answer»

AnswEr : $\\ \\$

$\star \sf \: Given\begin{cases} \: \: \: { \bf{Possible \: events = 6 }}\\ \\ \: \: \:{ \bf{No. \: on \: dice = 1,<klux>2</klux>,3,4,5 \: and \: 6}} \end{cases}$ $\\$

Now, we know the required formula for finding Probability.

That is, $\\$

$\: \: \: \: \star \: \: {\boxed{ \sf{ \purple{Probability = \dfrac{No. \: of \: favourable \: outcomes}{Total \: no. \: of \: favourable \: outcomes}}}}}$

(I) A Prime Number : $\\$

Prime numbers = 2, 3 & 5

$\\$

No. of favourable outcomes = 3

$\bigstar \:{ \underline{\sf \: Probability : }} \\ \\ : \implies\sf \: \dfrac{3}{6} \\ \\ : \implies\sf \: \blue{\dfrac{1}{2}} \\ \\$

(ii) A number lying between 2 and 5 : $\\$

Number's lying between 2 and 5 = 3 & 4

$\\$

No. of favourable outcomes = 2

$\bigstar \:{ \underline{\sf \: Probability : }} \\ \\ : \implies\sf \: \dfrac{2}{6} \\ \\ : \implies\sf \: \green{\dfrac{1}{3}} \\ \\$

(III) An EVEN number : $\\$

Even numbers = 2, 4 & 6

$\\$

No. of favourable outcomes = 3

$\bigstar \: { \underline{\sf \: Probability : }} \\ \\ : \implies\sf \: \dfrac{3}{6} \\ \\ : \implies\sf \: \orange{\dfrac{1}{2}} \\$

Pozz solve it.. ....

AnswEr : $\\ \\$