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PQ is a chord ofthe parabola `y^2=4x` whose perpendicular bisector meets the axis at M and the ordinate of the midpoint PQ meets the axis at N. Then the length MN is equal to |
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Answer» Correct Answer - 2 `P-=(t_(1)^(2),2t_(1))andQ-=(t_(2)^(2),2t_(2))` L is the midpoint of PQ. `:." "L-=((1)/(2)(t_(1)^(2)+t_(2)^(2)),(t_(1)+t^(2)))` `"Slope of PQ"=(2)/(t_(1)+t_(2))` `y-(t_(1)+t_(2))=(-(t_(1)+t_(2)))/(2)(x-(t_(1)^(2)+t_(2)^(2))/(2))` Putting y = 0, we get `M-=(2+(t_(1)^(2)+t_(2)^(2))/(2),0)` `N-=((t_(1)^(2)+t_(2)^(2))/(2),0)` `:." "MN=OM-ON=2` |
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