PQRS is a parallelogram with PS = 10 cm. T is a point on QR such that

1.	PQRS is a parallelogram with PS = 10 cm. T is a point on QR such that thearea of triangle PQT is 8 cm and QT = 4 cm. Calculate:a) the height, h of triangle PQT, b) the area of parallelogram PQRS.Please solve this sum as fast as u can
Answer» Answer: I hope it help you. Step-by-step explanation: For a parallelogram, ▶Opposite sides are equal. GIVEN, Area of parallelogram = 35 cm^2. Length of QR = RT + TQ Length of QR = 7 We know , Area of parallelogram = BASE × height Base = PQ = ? Height = QR = 7cm So, 35 = base ×7 35/7 = base 5CM = base For ΔPQT Base = PQ = 5cm Height = QT = 4cm Area of TRIANGLE = 1/2 × base × height Area of triangle = 1/2 × 7 × 4 Area of triangle = 1/2 × 28 Area of triangle =14 cm^2

PQRS is a parallelogram with PS = 10 cm. T is a point on QR such that thearea of triangle PQT is 8 cm and QT = 4 cm. Calculate:a) the height, h of triangle PQT, b) the area of parallelogram PQRS.Please solve this sum as fast as u can

Answer»

Answer:

I hope it help you.

Step-by-step explanation:

For a parallelogram,

▶Opposite sides are equal.

Area of parallelogram = 35 cm^2.

Length of QR = RT + TQ

Length of QR = 7

We know ,

Area of parallelogram = BASE × height

Base = PQ = ?

Height = QR = 7cm

So,

35 = base ×7

35/7 = base

5CM = base

For ΔPQT

Base = PQ = 5cm

Height = QT = 4cm

Area of TRIANGLE = 1/2 × base × height

Area of triangle = 1/2 × 7 × 4

Area of triangle = 1/2 × 28

Area of triangle =14 cm^2