Pqrs is a trapezium such that pq||rs and pq= 10cm, qr=5cm, rs=8cm, ps=

1.	Pqrs is a trapezium such that pq\|\|rs and pq= 10cm, qr=5cm, rs=8cm, ps=5cm then area of pqrs
Answer» Answer: Given: PQ is parallel to SR , PQ = 8 CM, ∠ PQR = 70 o QR = 6 cm and PS = 6 cm. Steps for construction Step 1 : DRAW a rough diagram and mark the given measurements. Step 2 : Draw a line segment PQ = 8 cm. Step 3 : At Q on PQ make ∠ PQX whose measure is 70 o . Step 4 : With Q as centre and 6 cm as radius draw an arc. This cuts $$\overline{QX}$$ at R. Step 5 : Draw RY parallel to OP . Step 6 : With Q as centre and radius 6 cm draw an arc cutting RY at S. Step 7 : Join PS . PQRS is the required trapezium. Step 8 : From S draw ST ⊥ PQ and measure the length of ST. ST = h = 5.6 cm, RS = b = 6 cm, PQ = a = 8 cm. Calculation of area: In the trapezium PQRS, a = 8 cm, b = 3.9 cm and h = 5.6 cm. Area of the trapezium ABCD = 2 1 h(a+b) = 2 1 (5.6)(8+3.9) = 2 1 × 5.6×11.9 =33.32 cm 2

Pqrs is a trapezium such that pq||rs and pq= 10cm, qr=5cm, rs=8cm, ps=5cm then area of pqrs

Answer»

Answer:

Given:

is parallel to

, PQ = 8 CM, ∠ PQR = 70

QR = 6 cm and PS = 6 cm.

Steps for construction

Step 1 : DRAW a rough diagram and mark the given measurements.

Step 2 : Draw a line segment PQ = 8 cm.

Step 3 : At Q on

make ∠ PQX whose measure is 70

Step 4 : With Q as centre and 6 cm as radius draw an arc. This cuts $$\overline{QX}$$ at R.

Step 5 : Draw

parallel to

Step 6 : With Q as centre and radius 6 cm draw an arc cutting

at S.

Step 7 : Join

. PQRS is the required trapezium.

Step 8 : From S draw

⊥

and measure the length of ST. ST = h = 5.6 cm, RS = b = 6 cm, PQ = a = 8 cm.

Calculation of area:

In the trapezium PQRS, a = 8 cm, b = 3.9 cm and h = 5.6 cm.

Area of the trapezium ABCD =

h(a+b)

(5.6)(8+3.9)

× 5.6×11.9

=33.32 cm