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Predict and explain the reactions: (a) Kl+Cl_(2)to (b) KClO_(3)+l_(2)to |
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Answer» Solution :(a) `2Kl+Cl_(2)to2KCl+l_(2)` (b) `KClO_(3)+l_(2)toKlO_(3)+Cl_(2)` Because in the FIRST CASE `Cl_(2)` is more powerful oxidizing agent than `l_(2)` and in second case `CIO_(3)^(-)` is more powerful oxidizing agent than `lO_(3)^(-)[Cl^(5+)]` being reduced to `Cl^(0)` and `L^(0)` being OXIDIZED to `l^(5+)`] |
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