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Predict the direction of induced current in the situations described by the following Figs. 6.03(a) to (f). |
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Answer» Solution :(a) In Fig. 6.03(a), on bringing the magnet nearer the coil pq, the nearer end q will behave as the south pole as per Lenz.s law i.e., the induced current will flow clockwise at q. Hence, in the coil, the induced current is from p to q or in the entire CIRCUIT induced current flows ALONG qrpq. (b) In this case, coil pg develops S-pole at q and coil XY also develops S-pole at X. Therefore, the induced current in coil pq will be from a top (or along prqp) and the induced current in coil XY will be from X to Y (or along XYZX). (c) As current in given coil is flowing clockwise and the current (i.c., the magnetic flux) is increasing because the tapping key has been just closed, the induced current in the 2ND coil will be in anticlockwise direction i.e., the induced current will flow along YZX. (d) As theostat SETTING is being changed in such a way that current in right loop is increasing. Hence, induced current in left loop will be, in accordance with Lenz.s law, in an opposite direction. Hence, as seen from the front the induced current in left loop will be along ZYX i.e., in clockwise direction. (e) As tapping key in electrical circuit of left side coil has just been released, current and hence magnetic flux in this coil is falling with time. Hence, in accordance with Lenz.s law induced current in the right side coil will also flow in same direction i.e., anticlockwise or along xry direction through the coil. (f) In this case magnetic field lines produced due to current flowing in straight wire are in the plane of given loop, hence no current is induced in the loop. |
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