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Predict the number of unpaired electrons in [CoCl_(4)]^(2-) ion on the basis of VBT. |
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Answer» Solution :`[CoCl_(4)]^(2-)` Electronic configuration of `Co` atom Electronic configuration of `Co^(2+)` ion Hybridisation and FORMATION of `[CoCl_(4)]^(2-)` complex `CL^(-)` isweak field ligand , THEREFORE no electrons pairing occurs. `sp^(3)` hybridisation It has `3` unpaired electrons hence it isparamagnetic Magentic moment, `mu_(s)=sqrt(N(n+2))` `=sqrt(3(3+2))=sqrt(15)=3.87BM` It has tetrahedral geometry. 
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