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Predict the number of unpaired electrons in the square planar [Pt(CN)_(4)]^(2-) ion. |
Answer» Solution :`._(78)Pt` lies in Group 10 with the configuration `5d^(9)6S^(1)`. Hence, `Pt^(2+)` has the configuration `d^(8)`  For square planar shape, the hybridisation is `dsp^(2)`. Hence, the unpaired ELECTRONS in 5d PAIR up to make one d-orbital empty for `dsp^(2)` hybridization. Thus, there is no unpaired ELECTRON. |
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