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Predict the product of the following reaction: C_(6)H_(5)-CO-CH_(3) overset(NaOH//I_(2))to?+? |
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Answer» Solution :`NaOH//I_(2)` i.e., sodium hypoiodite (NaIO) oxidises methyl ketones to `-COO^(-)Na^(+)+CHI_(3)-`IODOFORM reaction. `UNDERSET("Acetophenone")(C_(6)H_(5)-CO-CH_(3)) underset(("Iodoform reaction"))overset(NaOH//I_(2))to underset("Sod. BENZOATE")(C_(6)H_(5)-COO^(-)Na^(+))+underset("Iodoform")(CHI_(3))`. |
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