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Predict the product of the following reaction CH_(3)NO_(2)+C_(6)H_(5)CHO overset(KOH (alc.))to |
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Answer» Solution :DUE to the strong electron-withdrawing effect of the `NO_(2)` group, the H-atom of `CH_(3)NO_(2)` are weekly acidic. Therefore, in presence of KOH (alc.) it forms a carbanion (I) which adds to gtC=O group of `C_(6)H_(5)CHO` to form ALDOL (II) which SUBSEQUENTLY undergoes dehydration to form `beta`-nitrostyrene (or `beta`-nitrostyrene) `underset("Nitramethane")(CH_(3)NO_(2)) underset(-H_(2)O)overset(OH^(-)) tounderset("Carbanion (I)")(.^(-)CH_(2)-NO_(2)) overset(C_(6)H_(5)CH=O)to [underset((II))(C_(6)H_(5)-overset(OH)overset(|)(C)H-CH_(2)NO_(2))] underset(-H_(2)O)to underset("1-Nitro-2-phenylethene "(beta-"Nitrostyrene"))(C_(6)H_(5)overset(alpha)(C)H=overset(beta)(C)HNO_(2))` |
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