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Predict the sign of DeltaS in the following processes. Give reasons for your answer. (a) N_(2(g))+3H_(2(g))rarr2NH_(3(g)) (b) CO_(2(g))rarrCO_(2(s)) |
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Answer» Solution :`N_(2(G))+3H_(2(g))rarr2NH_(3(g))` In the reaction, 4 moles of gaseous reactants form 2 moles of gaseous products `(DELTA n LT 0)`. Therefore disorder decreases and hence entropy decreases, `DeltaS lt 0.` |
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