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Predict whether Ag^(+) can oxidize Pb to Pb^(2+) under standard state conditions. E_(Ag)^(@)=0.799V and E_(Pb)^(@)=-0.126V. |
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Answer» SOLUTION :(a) (i) Since the standard reduction potential of Ag under standard CONDITIONS is higher `(E_(Ag^(+)//Ag)=0.799V)` than that of `Pb(E_(Pb^(2+)//Pb)^(@)=-0.126V), Ag^(+)` have higher TENDENCY to gain electrons than Pb. (ii) Hence `Ag^(+)` acts as a STRONGER oxidising AGENT and oxidises Pb to `Pb^(2+)` while `Ag^(+)` gets reduced to Ag. The redox reaction will be, `Pb_((s))+2Ag_((aq))^(+) rarr Pb_((aq))^(2+)+2Ag_((s))` |
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