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Preparation of alcohols from alkenes involves the electrophilic attack on alkene carbon. Explain its mechanism. |
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Answer» Solution :`to`Step-1: Electrophilic attack by hydronium ion (`H_(2)O^(+)`) on alkene gives an intermediate. CARBOCATION. `(H_(2)SO_(4) to H^(+)+ ""^(-)OSO_(2)OH)` `H- underset(* *)overset(* *) O -H+ H^(+) to underset("Hydrominum ion")( H-underset(* *)overset(H)overset(|)overset(+)O- H(H_(3)O^(+)))` ![]() Step-2 : Nucleophilic attack by water on carbocation to yield protonated ALCOHOL. Step-3: Deprotonation (loss of proton) to form an alcohol.
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