Pressure and volume of a gas changes from `(p_0V_0)` to `(p_0/4, 2V_0)` in a process `pV^2=` constant. Find work done by the gas in the given process.

Pressure and volume of a gas changes from `(p_0V_0)` to `(p_0/4, 2V_0)

1.	Pressure and volume of a gas changes from `(p_0V_0)` to `(p_0/4, 2V_0)` in a process `pV^2=` constant. Find work done by the gas in the given process.
Answer» Correct Answer - A::B `pV^2=K=p_0V_0^2` `:.` `p=(K)/(V^2)` `W=intpdV=int_(V_0)^(2V_0)(K)/(V^2)dV` `=[-(K)/(V)]_(V_0)^(2V_0)` `=(K)/(V_0)-(K)/(2V_0)` `(K)/(2V_0)` Substituting, `K=p_0V_0^2`, we have `W=1/2p_0V_0`

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Pressure and volume of a gas changes from `(p_0V_0)` to `(p_0/4, 2V_0)` in a process `pV^2=` constant. Find work done by the gas in the given process.

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