InterviewSolution
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InterviewSolution
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Pressure exerted by a perfect gas equal toA. mean `K.E.` per unit volumeB. half of mean `K.E.` per unit volumeC. one-third of mean `K.E.` per unit volumeD. two-third of mean `K.E.` per unit volume |
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Answer» Correct Answer - D `P = (1)/(3) (M)/(V) v_(rms)^(2) = (2)/(3)(((1)/(2)Mv_(rms)^(2))/(V))` `= (2 K)/(3V), K :K.E`. |
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