1.

Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere. Ratio between their volumes is :

Answer»

`102:101`
`(102)^(3):(103)^(3)`
`8:1`
`2:1`

SOLUTION :`P_(i)-P_(0)=(4T)/(R_(1))`
`rArrR_(1)=(4T)/(1.01-1)=(4T)/(0.01)`
Similarly for SECOND bubble,
`R_(2)=(4T)/(1.02-1)=(4T)/(0.02)`
Now `(R_(1))/(R_(2))=(0.02)/(0.01)=2`
`therefore(V_(1))/(V_(2))=((R_(1))/(R_(2)))^(3)=8`
Hence the CORRECT choice is (C).


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