1.

Pressure of 0.210 bat at 37^(@)C. The vapour pressure of pure liquid (vapour pressure of water at 37^(@)C=0.198 bar in bar is

Answer»

0.448
44.8
0.224
2.24

Solution :Mole FRACTION of LIQUID `A`, `chi_(l)=0.2/(0.2 + 4.0)=0.048`
Mole fraction of water, `chi_(w)=1.0-0.048=0.952`
`0.210=P_(t)^(@)chi_(l) + P_(w)^(@)chi_(w)`
`0.210=P_(l)^(@) XX 0.048 + 0.198 xx 0.952`
`P_(l)^(@)=(0.210-0.198 xx 0.952)/0.048 =0.448 "BAR"`


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