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Pressure over 1000 mlof a liquid is gradually increases from1 barto 1001 bar underadiabiticconditions. Ifthe finalvolumeof the liquid is 990 ml, calculateDeltaU and DeltaH of the process, assuminglinear variationof volume with pressure . |
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Answer» `=(1)/(2) xx(1000 xx 10 xx 10^(-3))+ 10 xx 10^(-3)` `= 5.01 "bar"-L"" = 501 J` `= 501 J` `Q=0` `Delta U = 501 J""(DELTAU= q +W)` DeltaH = DeltaU + Delta(PV) = DeltaU + (P_(2)V_(2)- P_(1)V_(1)) ` = 501+[1001 xx 990 xx 10^(-3) - 1 xx 10^(-3)xx 10^(-3)] xx 100= 501 + 98999 J` `DeltaH = 99.5 KJ`
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