Probability of getting no head when 3 coins are tossed isA) 3/23B) 2/2

1.	Probability of getting no head when 3 coins are tossed isA) 3/23B) 2/23C) 1/32D) 1/23
Answer» Correct option is: D)\(\frac{1}{2^3}\) When 3 coins are tossed, total possible outcomes are {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} \(\therefore\) Total No of possible outcomes when 3 coins are tossed = 8 = \(2^3\) Fabourable outcome that favours to event of getting no head is {TTT} \(\therefore\) Total fabourable outcomes = 1 \(\therefore\) Probability of getting no head = \(\frac {Total \,favourable\, outcomes}{Total \,No \,of \,possible \,outcomes}\) = \(\frac 18 = 2^{\frac 13}\) Correct option is: D) \(\frac{1}{2^3}\)

Probability of getting no head when 3 coins are tossed isA) 3/23B) 2/23C) 1/32D) 1/23

Answer»

Correct option is: D)\(\frac{1}{2^3}\)

When 3 coins are tossed, total possible outcomes are

{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

\(\therefore\) Total No of possible outcomes when 3 coins are tossed

= 8 = \(2^3\)

Fabourable outcome that favours to event of getting no head is {TTT}

\(\therefore\) Total fabourable outcomes = 1

\(\therefore\) Probability of getting no head = \(\frac {Total \,favourable\, outcomes}{Total \,No \,of \,possible \,outcomes}\) = \(\frac 18 = 2^{\frac 13}\)

Correct option is: D) \(\frac{1}{2^3}\)

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