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Proove that: √3+1) ( 3 - Cot 30) - tan³60 - 2 sin60​

Answer» LHS=( 3 +1)(3−COT30)=3 3 − 3 cot30+3−3cot30=3 3 − 3 cot30+ 3 3 − 3 3 cot30=3 3 − 3 cot30(1+ 3 )+3=3 3 − tan30cot30 (1+ 3 )+3=3 3 − tan30cot30 tan45− tan30tan30cot30 +cot 2 30=tan 3 60−2sin60


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