1.

Propanol is heated with conc. H_(2)SO_(4) at 170^(@)C and the gas produced is reacted with HBr. What is the formula of the final product ?

Answer»

`CH_(3) - CH_(2) CH_(2)Br`
`CH_(3) underset(Br)underset(|)(CH)-underset(Br)underset(|)(CH_(2))`
`CH_(3) - underset(Br)underset(|)(CH) - CH_(2)OH`
`CH_(3) - underset(Br)underset(|)(CH) - CH_(3)`

SOLUTION :Dehydration of propanol with CONC. `H_(2)SO_(4)` gives propene which reacts with HBr to form
`CH_(3) underset(Br)underset(|)(CH) - CH_(3)` (Markovnikov.s rule).


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