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Propose the mechanism of the reaction taking place when: (a). (-)-2-Bromooctane reacts with sodium hydroxide to form (+)-Octane-2-ol. (b). 2-Bromopentane is heated with KOH (alc). To form alkene. |
Answer» Solution :(a). In this reaction, there is an inversion of configuration and `OH^(-)` ion (nucleophile) attacks from a side opposite to the side where Br atom is PRESENT. This means that the reaction FOLLOWS `S_(N^(1))` MECHANISM.  (B). In this reaction bimolecular elimination (`E_(2)`-elimination) takes place.  .
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