Prove (sin^3theta + cos^3theta) = (sintheta + costheta) (1-sintheta.co

1.	Prove (sin^3theta + cos^3theta) = (sintheta + costheta) (1-sintheta.costheta)
Answer» Step-by-step explanation: LHS = ( sin^3θ + cos^3θ ) a^3 + b^3 = (a + b)(a^2 - ab + b^2) = (sinθ + cosθ) ( sin^2θ - sinθ.cosθ + cos^2θ) sin^2θ + cos^2θ = 1 = ( sinθ + cosθ )( 1 - sinθ .cosθ ) = RHS hence proved (☺️) I HOPE this will HELP you.... plz follow me..

Prove (sin^3theta + cos^3theta) = (sintheta + costheta) (1-sintheta.costheta)

Answer»

Step-by-step explanation:

LHS = ( sin^3θ + cos^3θ )

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

= (sinθ + cosθ) ( sin^2θ - sinθ.cosθ + cos^2θ)

sin^2θ + cos^2θ = 1

= ( sinθ + cosθ )( 1 - sinθ .cosθ )

= RHS

hence proved (☺️)

I HOPE this will HELP you....

plz follow me..