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Prove that √1+Cotθ /1-Cotθ=Cosecθ+Cotθ |
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Answer» -STEP explanation:LHS - Multiplying both NUMERATOR & DENOMINATOR by 1−cosθ(1+cosθ)(1−cosθ)(1−cosθ)(1−cosθ)⇒1−cos2θ(1−cosθ)2 {∵sin2x+cos2x=1}⇒sin2θ(1−cosθ)2⇒(sinθ)∣1−cosθ∣taking + VALUES only positive.⇒sinθ1−cosθ⇒sinθ1−sinθcosθ⇒cosecθ−cotθ = RHS |
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