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Prove that √18 is irrational

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Answer:

According to the theorem, it FOLLOWS that √18 is either an integer or an irrational number. Because it is not an integer (for 18 is not a perfect SQUARE, i.e. 18 is not the square of an integer), it is irrational. In GENERAL, if x is a positive integer, and q√x is not an integer, then it will be irrational.

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