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Prove that:2sin75°sin15° = 1/2 |
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Answer» L.H.S = 2sin75°sin15° = 2sin(45° + 30°)sin(45° - 30°) = cos(45° - 30° - 45° - 30°) - (cos45° + 30° + 45° - 30°) = cos(-60°) - cos90° = cos60° - 0 = \(\frac{1}{2}\) |
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