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Prove that `2sqrt3` is an irrational number

Answer» Rational numbers can be written in the form `p/q` where `p` and `q` are intergers and `q !=0`.
Now, given number is ,
`2sqrt3 = 2sqrt3**sqrt3/sqrt3 = 6/sqrt3`
So, it is in `p/q` form and `q !=0`.
But, as `q` is not an integer,
given number is not a rational number.
Hence, `2sqrt3` is an irrational number.


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