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Prove that `2sqrt3` is an irrational number |
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Answer» Rational numbers can be written in the form `p/q` where `p` and `q` are intergers and `q !=0`. Now, given number is , `2sqrt3 = 2sqrt3**sqrt3/sqrt3 = 6/sqrt3` So, it is in `p/q` form and `q !=0`. But, as `q` is not an integer, given number is not a rational number. Hence, `2sqrt3` is an irrational number. |
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