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Prove that 3(√2a)(2b)(-3c) = 18√2abc |
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Answer» QUESTION - 2√2a^3+8b^3-27c^3+18√2abc Answer :- =>2√2a³+8b³-27c³+18√2abc =>(√2a)³+(2B)³+(-3C)³-3(√2a)(2b)(-3c) =>(√2a+2b-3c)(2a²+4b²+9c²-2√2ab+6bc+3√2ca) THANK you! ❤ |
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