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Prove that 5 – √3 is irrational. |
Answer» Let 5 – √3 is a rational number. we have to find out two integers a and b such as 5 - √3 = a/b - √3 = a/b - 5 √3 = 5 - a/b √3 = (5b - a)/b a, b and 5 all are integers (5b - a)/b is a rational number. √3 will be also rational number. But this contradicts the fact that √3 is an irrational number. So our hypothesis is wrong. Hence, 5 – √3 is an irrational number. |
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