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Prove that √6 + OVE is prontional |
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Answer» he following PROOF is a proof by CONTRADICTION. Let us assume that 6 is rational number. Then it can be represented as fraction of two INTEGERS. Let the lowest TERMS representation be: 6 = b a where b =0 Note that this representation is in lowest terms and HENCE, a and b have no common factors a 2 =6b 2 From above a 2 is even. If a 2 is even, then a should also be even. ⟹a=2c 4c 2 =6b 2 2c 2 =3b 2 From above 3b 2 is even. If 3b 2 is even, then b 2 should also be even and again b is even. But a and b were in lowest form and both cannot be even. Hence, assumption was wrong and hence, 6 *^ is an irrational number.Step-by-step explanation: |
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