Prove that 7+3√2 is an irrational number , where root 2 is given to

1.	Prove that 7+3√2 is an irrational number , where root 2 is given to be an irrational number.
Answer» Step-by-step explanation: given Root 2 is irrational.... let, assume that the NUM is rational so,.. 7+3root2=a/b ( where a and b are coprime) 3root2=a-7b/b co-prime mean HCF=1 root 2=a-7b/3b we KNOW that root2 is irrational it contradicts assumsion that the NUMBER is rational... so the number 7+3root2 is irrational... Hence,Proved... Hope it HELPS u.... Plz mark as Brainliest!....

Prove that 7+3√2 is an irrational number , where root 2 is given to be an irrational number.

Answer»

Step-by-step explanation:

given Root 2 is irrational....

let, assume that the NUM is rational

so,..

7+3root2=a/b ( where a and b are coprime)

3root2=a-7b/b co-prime mean HCF=1

root 2=a-7b/3b

we KNOW that root2 is irrational

it contradicts assumsion that the NUMBER is rational...

so the number 7+3root2 is irrational...

Hence,Proved...

Hope it HELPS u....

Plz mark as Brainliest!....

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Prove that 7+3√2 is an irrational number , where root 2 is given to be an irrational number.

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