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Prove that √7 is irrational |
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Answer» a rational number is a number which in which both numerator and denominator BELONG to integers, both the numbers are coming prime, denominator is not equal to 0, it should be in p/q FORM. Step-by-step EXPLANATION: assume √7 as a rational number a/b=√7 a=(√7)*b squaring both sides a square= (√7)square*b square a square=7b square a square is divisible by 7 then a is also divisible by 7 a=7c squaring both sides a square=7 square*c square a square=49*c square 7b square=49c square b square=49c square/7 b square=7c square a and b are not Co-prime so it is not a rational number. THEREFORE it is a irrational number. this contraductory has arised DUE to our wrong assumption that√7 is a rational number. |
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