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Prove that `(9pi)/(8)-(9)/(4)sin^(-1)""(1)/(3)=(9)/(4)sin^(-1)""(2sqrt(2))/(3)` |
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Answer» We have, LHS `=(9pi)/8-9/4sin^(-1)1/3` `9/4(pi/2-sin^(-1)1/3)`. `=9/4cos^(-1)1/3=9/4sin^(-1)sqrt(1-1/9)` `9/4sin^(-1)(2sqrt(2))/(3)`=RHS Hence, LHS=RHS |
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