Prove that a4 digits palindrome is always divisible by 11

1.	Prove that a4 digits palindrome is always divisible by 11
Answer» Answer: HEY... Explanation: Suppose a and b are digits, and we consider the palindrome that looks like abba. Step-by-step explanation: Now, abba = 1000a + 100b + 10b + a. We can REARRANGE this to 1000a + a + 100b + 10b = 1001a + 110b. Now, 1001 = 7 * 11 * 13, and 110 = 2 * 5 * 11, so, abba = 1001a + 110b = 11 * (713a + 25b) So abba is a multiple of 11. Here's a specific example: 3223 = 3000+200+20+3 = 3003+220 = 11273+1120 = 11*293 plzzz MARK as brainliest naswer

Answer»

Answer:

HEY...

Explanation:

Suppose a and b are digits, and we consider the palindrome that looks like abba.

Step-by-step explanation:

Now, abba = 1000*a + 100*b + 10*b + a.

We can REARRANGE this to

1000*a + a + 100*b + 10*b = 1001*a + 110*b.

Now, 1001 = 7 * 11 * 13, and 110 = 2 * 5 * 11,

so, abba = 1001*a + 110*b = 11 * (7*13*a + 2*5*b)

So abba is a multiple of 11.

Here's a specific example:

3223 = 3000+200+20+3 = 3003+220

= 11*273+11*20 = 11*293

plzzz MARK as brainliest naswer

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