Prove that by adding the points (2,0), (5,0), (6,2), and (3,2) one aft

1.	Prove that by adding the points (2,0), (5,0), (6,2), and (3,2) one after the other, a parallelogram is formed.
Answer» GIVEN points are A(2,0) B(5,0) C(6,2) D(3,2) *A quadrilateral is a parallelogram if the opposite sides are equal.* AB² = (2-5)² + (0-0)² = 9 + 0 = 9 ⇒ AB = ±3 BC² = (5-6)² + (0-2)² = 1 + 4 = 5 ⇒ BC = √5 CD² = (6-3)² + (2-2)² = 9 + 0 = 9 ⇒ CD = ±3 DA² = (3-2)² + (2-0)² = 1 + 4 = 5 ⇒ DA = √5 ∴ AB = CD = ±3 & BC = DA = √5 ∴ The opposite sides of the quadrilateral ABCD are equal, the four points from a parallelogram. HENCE PROVED !!!!!!

Prove that by adding the points (2,0), (5,0), (6,2), and (3,2) one after the other, a parallelogram is formed.

Answer»

GIVEN points are

A(2,0)

B(5,0)

C(6,2)

D(3,2)

A quadrilateral is a parallelogram if the opposite sides are equal.

AB² = (2-5)² + (0-0)² = 9 + 0 = 9 ⇒ AB = ±3
BC² = (5-6)² + (0-2)² = 1 + 4 = 5 ⇒ BC = √5
CD² = (6-3)² + (2-2)² = 9 + 0 = 9 ⇒ CD = ±3
DA² = (3-2)² + (2-0)² = 1 + 4 = 5 ⇒ DA = √5

∴ AB = CD = ±3 & BC = DA = √5

∴ The opposite sides of the quadrilateral ABCD are equal, the four points from a parallelogram.

HENCE PROVED !!!!!!

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Prove that by adding the points (2,0), (5,0), (6,2), and (3,2) one after the other, a parallelogram is formed. ​

∴ AB = CD = ±3 & BC = DA = √5

∴ The opposite sides of the quadrilateral ABCD are equal, the four points from a parallelogram.

HENCE PROVED !!!!!!

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Prove that by adding the points (2,0), (5,0), (6,2), and (3,2) one after the other, a parallelogram is formed.