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Prove that cos(3π/2 + x)cos(2π + x) [cot(3π/2 - x) + cot(2π + x)] = 1 |
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Answer» LHS = (sinx)cosx[tanx + cotx] = sinxcosx[sinx/cosx + cosx/sinx] = sin2x + cos2x = 1 = RHS. |
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