1.

Prove that cos(3π/2 + x)cos(2π + x) [cot(3π/2 - x) + cot(2π + x)] = 1

Answer»

LHS = (sinx)cosx[tanx + cotx]

= sinxcosx[sinx/cosx + cosx/sinx]

= sin2x + cos2x

= 1 = RHS.



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