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Prove that cos(π/4 + x) + cos(π/4 - x) = √2cosx |
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Answer» LHS = cos(π/4)cosx - sin(π/4)sinx + cos(π/4)cosx + sin(π/4)sinx = 2cos(π/4)cosx = 2(1/√2)cosx = √2cosx = RHS |
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