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Prove that cos theta by 1 - sin theta equals to 1 + sin theta by cos theta​

Answer»

The given EQUATION is:

\frac{cos\THETA}{1+sin{\theta}}=\frac{1-sin{\theta}}{cos{\theta}}

TAKING the LHS of the above equation, we have

\frac{cos\theta}{1+sin{\theta}}

=\frac{cos\theta}{1+sin{\theta}}{\times}\frac{1-sin\theta}{1-sin{\theta}}

=\frac{cos\theta(1-sin\theta)}{1-sin^2{\theta}}

=\frac{cos\theta(1-sin\theta)}{cos^2{\theta}}

=\frac{1-sin{\theta}}{cos{\theta}}

=RHS

Hence proved.



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