Prove that every point on the bisector of an angle is equidistant from – InterviewSolution

1.

Prove that every point on the bisector of an angle is equidistant from the sides of the angle

Answer»

Step-by-step explanation:

we NEED to show BP=CP

In RIGHT angles △ABP

sinα=

AP

BP

...(i)

in right ANGLED △ACP

sinα=

AP

CP

...(ii)

from (i) & (ii)

AP

BP

=

AP

CP

BP=CP

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