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Prove that for a projectile fired from level ground at an angle `theta` above the horizontal, the ratio of the maximum height H to the range R is given by `(H)/(R)=(1)/(4)tan theta` |
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Answer» `H=(u^(2)sin ^(2)theta)/(2g)` and `R=(u^(2)sin2 theta)/(g)` `(H)/(R)=(sin ^(2)theta)/(2sin 2theta)=(sin^(2)theta)/(4sin theta cos theta)=(1)/(4) tan theta` |
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