1.

Prove that (i) `[hat(i)hat(j)hat(k)]=[hat(j)hat(k)hat(i)]=[hat(k)hat(j)hat(i)]=1` (ii)`[hat(i)hat(k)hat(j)]=[hat(k)hat(j)hat(i)]=[hat(j)hat(i)hat(k)]=1`

Answer» Correct Answer - B
`[hat(i)hat(j)hat(k)]=(hat(i)xxhat(j)).hat(k)=hat(k).hat(k)=1`.


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