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Prove that in a uniform field the work is independent of the path. |
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Answer» SOLUTION :Let the object move in the field from POINT M to point Nfirst along the rectilinear segment MN=l, and then along the broken line `MKN = l_(1)+l_(2)`, In the first case the work done is `A= Fl cos alpha =Fd` In the second case the work done is `A= A_(1)+A_(2)=Fl_(1) cosalpha_(1)+fl_(2)cosalpha_(2)=F(l_(1)cos alpha_(1)+l_(2)cosalpha_(2))=Fd`  We see that the work done is independent of the PATH. |
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