Saved Bookmarks
| 1. |
Prove that:(its urgent plz help someone who's intelligent enough !!) |
|
Answer» LET x = TAN A , y = Tan B , z = Tan C (x - y)/(1+x y) = tan (A-B) (y-z)//(1+y z) = tan (B-C) (z-x)/(1+z x) = tan (C - A) LHS = (A-B) + (B-C) + (C-A) = 0 RHS is also similar to LHS. If we assume x³ = tan P , y³ = tan Q , z³ = tan R RHS = tan⁻¹ (tan (P-Q) ) + tan⁻¹ [tan (Q-R) ] + tan⁻¹ [ tan (R-P) ] = 0 LHS = RHS |
|