prove that `(p^^q) ^^~(pvvq)` is a contradiction. – InterviewSolution

1.	prove that `(p^^q) ^^~(pvvq)` is a contradiction.
Answer» `(p^^q)^^~(pvvq) -=(p^^q)^^(~p^^~q)` `-=(p^^~p) ^^(q^^~q)` `-=f^^f` `-=f` thus, `(p^^q)^^~(pvvq)` is fallacy, i.e., contradiction.

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