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prove that : sin 48 sec 42 + cos 48 cosec 42 =2 |
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Answer» LHS=`sin48/cos42+cos48/sin42` `=(sin48sin42+cos48cos42)/(sin42cos42)` `=cos(48-42)/(sin42cos42)` `=(2cos6)/sin84` `=2cos6/cos6` `=2=RHS` hence proved. |
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