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prove that : sin 48 sec 42 + cos 48 cosec 42 =2

Answer» LHS=`sin48/cos42+cos48/sin42`
`=(sin48sin42+cos48cos42)/(sin42cos42)`
`=cos(48-42)/(sin42cos42)`
`=(2cos6)/sin84`
`=2cos6/cos6`
`=2=RHS`
hence proved.


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