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Prove that sin8x = 8sinx.Cosx.Cos2x.Cos4x​

Answer»

please mark me as the brainliestStep-by-step explanation:Apply the 2 trig identity: sin 2A = 2SIN a.cos a sin 8X = 2sin 4X.cos 4x. SINCE sin 4x = 2sin 2x.cos 2x, therefor, sin 8x = 2(2sin 2x.cos 2x)cos 4x =



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