1.

Prove that `tan^(-1)((cosx-sinx)/(cosx+sinx))=(pi/4-x), x lt pi`.

Answer» We have,
LHS `=tan^(-1)((cosx-sinx)/(cosx+sinx))`
`=tan^(-1)((1-tanx)/(1+tanx))` [dividing num. and denom. By `cos x`]
`=tan^(-1){tan(pi/4-x)}=(pi/4-x)` RHS.
`therefore tan^(-1)((cosx-sinx)/(cosx+sinx))=(pi/4-x)`.


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