prove that tan a divided by 1 minus cot A + cot a divided by 1 minus 10 is equal to 1 + 10 A + cot a is equal to 1 + sec cosec

prove that tan a divided by 1 minus cot A + cot a divided by 1 minus 1

1.	prove that tan a divided by 1 minus cot A + cot a divided by 1 minus 10 is equal to 1 + 10 A + cot a is equal to 1 + sec cosec
Answer» -step explanation: The proof of the given equality is as FOLLOWS : tanA1−cotA+cotA1−tanA=sinAcosA1−cosAsinA+cosAsinA1−sinAcosA =sin2AcosA(sinA−cosA)+cos2AsinA(cosA−sinA) =sin3A−cos3AcosAsinA(sinA−cosA) =sin2A+cosAsinA+cos2AcosAsinA =1+cosAsinAcosAsinA =1+secAcscA. tan A/1-cot A + cot A/1-tan A = 1+sec A cosec A HENCE PROVED. Please MARK me as the BRAINLIEST

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prove that tan a divided by 1 minus cot A + cot a divided by 1 minus 10 is equal to 1 + 10 A + cot a is equal to 1 + sec cosec​

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prove that tan a divided by 1 minus cot A + cot a divided by 1 minus 10 is equal to 1 + 10 A + cot a is equal to 1 + sec cosec