1.

Prove that:\(tan\frac{π}{12}+tan\frac{π}6+tan\frac{π}{12}tan\frac{π}6\) = 1

Answer»

⇒ π/12 = 15° And π/6 = 30° 

We have 15° + 30° = 45° 

⇒ tan(15° + 30°) = tan 45° 

We know that tan(A + B) = \(\frac{tanA+tanB}{1-tanAtanB}\)

⇒ \(\frac{tan15°+tan30°}{1-tan15°tan30°}\) = 1

⇒ tan15° + tan30° = 1 – tan15° tan30° 

∴ tan15° + tan30° + tan15° tan30° = 1 

Hence, proved.



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