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Prove that:\(tan\frac{π}{12}+tan\frac{π}6+tan\frac{π}{12}tan\frac{π}6\) = 1 |
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Answer» ⇒ π/12 = 15° And π/6 = 30° We have 15° + 30° = 45° ⇒ tan(15° + 30°) = tan 45° We know that tan(A + B) = \(\frac{tanA+tanB}{1-tanAtanB}\) ⇒ \(\frac{tan15°+tan30°}{1-tan15°tan30°}\) = 1 ⇒ tan15° + tan30° = 1 – tan15° tan30° ∴ tan15° + tan30° + tan15° tan30° = 1 Hence, proved. |
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