1.

Prove that: `tan(pi/4+A). Tan((3pi)/4)+A=-1`

Answer» LHS `=tan(pi/4+A).tan((3pi)/4+A)`
`=tan(pi/4+A).tan{pi/2+(pi/4+A)}`
`tan(pi/4+A).{-cot(pi/4+A)}`
`=-tan(pi/4+A).1/(tan(pi/4+A))`
`=-1`=RHS Hence proved.


Discussion

No Comment Found

Related InterviewSolutions